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E maths - Coordinate Geometry

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  • bonkysleuth
    bonkysleuth's Avatar
    214 posts since Mar '07
    • 05 May `08, 9:22PM

      the vertice of the triangleABC are A(-4,1), B(-4,-2) and C(2,5). find

       

      just answer question d. the earlier questions may well serve you as a reference .

       

      (a) the equations of the lines AB, BC, CA

      (b) coordinates of the point where AC cuts tge y0axis

      (c) area of triangle ABC

      (d) perpendicular distance from A to BC

  • Queen of sgForums
    FireIce
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    154,775 posts since Dec '99
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    eagle
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    15,439 posts since Aug '01
    • 05 May `08, 9:40PM

      pls give the answers for the first few parts so that there's no necessity to do extra work. If possible, provide the answer for part d too. Thanks.

  • bonkysleuth
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    214 posts since Mar '07
    • 05 May `08, 9:54PM

      (a) AB : x = -4

      BC : y = 7/6 x + 8/3

      CA : y = 2/3x +11/3

       

      b. (0, 11/3)

       

      (c) 9 units 2

      (d) 1.95 units

  • Moderator
    eagle
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    15,439 posts since Aug '01
    • 05 May `08, 9:57PM

      length BC = sqrt (7^2 + 6^2) = sqrt(85)

      0.5 * length BC * perpendicular distance from A to BC = area of triangle ABC

      0.5 * sqrt(85) * perpendicular distance from A to BC = 9 (from part c)

      perpendicular distance from A to BC = 1.95 units

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